How to loop through a matrix, one row at a time using a for loop and conditions

So I have a 4x2 matrix

Matrix = [20,5; 30, -6; 40,8; 50,10];

. And I want to create a for loop with if-else statement that goes through the matrix and test if either the row or col value is negative, then it would display something like 'neg'. If both values are positive, then there will be a function called; (lets say the function is called Func).

how do I go through and test each row and col value to see if it is neg or pos?

thanks

Answer 1

[madhan ravi]

Read about logical indexing:

Matrix = [20,5; 30, -6; 40,8; 50,10];
for i = 1:size(Matrix,1)
if Matrix(i,1)<0 || Matrix(i,2)<0
    disp('neg')
elseif Matrix(i,1)>0 && Matrix(i,2)>0
% some function
end
end

[DEBORAH]

Why can't I do this: for i = 1:size(Matrix(:,1)?

Answer 2

[Stephen23]

Simpler:

M = [20,5;30,-6;40,8;50,10]
X = all(M>=0,2)
for k = 1:size(M,1)
    if X(k)
        M(k,:)
    end
end