How to efficiently encode two values as a unique entitiy
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balandong
am 23 Nov. 2018
Beantwortet: Andrei Bobrov
am 23 Nov. 2018
Dear all,
With respect to the above subject, I wonder if we can make the following code more efficient and compact (reduce the ifelse)..
A=3;
B=3;
C=[];
if A==1 && B==1
C=1;
elseif A==1 && B==2
C=2;
elseif A==1 && B==3
C=3;
elseif A==2 && B==1
C=4;
elseif A==2 && B==2
C=5;
elseif A==2 && B==3
C=6;
elseif A==3 && B==1
C=7;
elseif A==3 && B==2
C=8;
elseif A==3 && B==3
C=9;
end
In addition, I also wonder if we can scale it up for A=[2;2;3;1] and B= [1;1;3;1]
Thanks in advance
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Andrei Bobrov
am 23 Nov. 2018
in your case:
>> A=[3;3;3;1]; B= [1;1;3;1];
f = @(A,B) 3*(A(:) - 1) + B(:);
C = f(A,B)
C =
7
7
9
1
>>
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