Plotting a spiral in MATLAB knowing the start and end points and number of turns?

23 Ansichten (letzte 30 Tage)
I found a code and was able to modify it into the following code to creaet a spiral that starts at the point I want it to but I can't seem to get it to end where I want it to and have the desired numer of turns.
t = 1:5000;
u = .0265;
r0 = 10;
r = r0 +u*t;
omega = .005;
phi0 = 3*pi/2;
phi = -omega*t+phi0;
x = r .* cos(phi);
y = r .* sin(phi);
plot(x,y)
grid on;
  1 Kommentar
Jacob Shulman
Jacob Shulman am 23 Nov. 2018
where do you want it to stop? you'll have to just figure out the value of t at that point. currently you have 5000 values of t. To shorten the spiral, shorten the array t.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Jos (10584)
Jos (10584) am 23 Nov. 2018
This does the job (for an integer number of turns)
% given values
pos = [8 4 ; % startpoint
2 7 ] ; % endpoint
nturns = 3 ; % number of turns (integer value)
% engine
dp = diff(pos,1,1) ;
R = hypot(dp(1), dp(2)) ;
phi0 = atan2(dp(2), dp(1)) ;
phi = linspace(0, nturns*2*pi, 10000) ; % 10000 = resolution
r = linspace(0, R, numel(phi)) ;
x = pos(1,1) + r .* cos(phi + phi0) ;
y = pos(1,2) + r .* sin(phi + phi0) ;
plot(x,y,'b-',pos(:,1),pos(:,2),'ro-') ; % nturns crossings, including end point
  7 Kommentare
km meenu
km meenu am 19 Jul. 2020
I have a code of galaxy model and spiral line code how i draw the spiral line in the spiral arms of the galaxy

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Startup and Shutdown finden Sie in Help Center und File Exchange

Produkte


Version

R2017b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by