I want make a loop in which when i complete it's 5 turns then J =J+1. and repeat it until J does not approach to it's maximum given value ?

here i =1:5 and j=2:8

but, for eachtime when i arrive at 5, j=j+1

[(A(:,j).visited(i,:)]

end

[Dennis]

for j=2:8
    for i=1:5
%do stuff
    end
end

[Jan]

@Xinyue Lan: The question is not clear.

[Xinyue Lan]

@Dennis thank you very much, but i want to save the output array into D, it is holding only one set of solution, not whole string of solution.

for j= 2:8

for i=1:5

D=[A(:,j).visitd(i,:)]

end

end

[madhan ravi]

D(j,i)=[A(:,j).visitd(i,:)]  %this will save your output as you want

[Xinyue Lan]

error: Unable to perform assignment becuase the size of the left side is 1-by-1 and the size of the right side is 1-by-2.

[Walter Roberson]

D(j,i,:) on the left side of the assignment .

[Xinyue Lan]

conversion to cell from double is not possible

Error

D(j,i,:)=[A(:,j).visited(i,:)];

[Walter Roberson]

assign to D{i,j}

however unless A has only one row and j is a scalar then you would get an indexing error . In matlab it is not possible to use a single statement to access a subset of an field inside a nonscalar structure array. You can have

scalar_structure

scalar_structure.fieldname

scalar_structure.fieldname(index)

nonscalar_structure

nonscalar_structure.fieldname

nonscalar_structure(index)

nonscalar_structure(index).fieldname

nonscalar_structure(scalar_index).fieldname(index)

but you cannot have nonscalar_structure(nonscalar_index).fieldname(index)

[Xinyue Lan]

bro, actually A is a 1x9 struct with 2fields. size(A)= [1 9]. the output

for j=2:8

for i= 1:5

D=[A(:,j).visited(i,:)]

end

end

here D has a continous output of solution set each of (1-by-2), and i want store total solutions size=40x2 into D .

kindly help me regarding this