I havent had to use matlab before. When i type out the code I was given it won't run because of an invalid expression. i can't figure out my mistep
close all
clear all
t=0;
theta0=pi()/3;
L=.5;
lam=6;
for n=1:161
t(n+1) =t(n)+.02;
theta(n)=theta0*sin(lam*t(n));
omega(n)=lam*theta0*cos(lam*t(n));
alpha(n)=-lam^2*theta(n);
xA(n)=t(n);
yA(n)=t(n)^(3)/18;
xB(n)=xA(n)+L*sin(theta(n));
yB(n)=yA(n)-L*cos(theta(n));
uA(n)=1;
vA(n)=t(n)^(2)/6;
uB(n)=uA(n)+L*omega(n)*cos(theta(n));
vB(n)=vA(n)+L*omega(n)*sin(theta(n));
axA(n)=0;
ayA(n)=t(n)/3;
axB(n)=L*alpha(n)*cos(theta(n))-L*omega(n)^2*sin(theta(n));
ayB(n)=ayA(n)+L*alpha(n)*sin(theta(n))+L*omega(n)^2*cos(theta(n));
end;
for n=1:161
line([xA(n) xB(n)]),[yA(n) yB(n)]);
end

 Akzeptierte Antwort

madhan ravi
madhan ravi am 3 Nov. 2018
Bearbeitet: Stephen23 am 3 Nov. 2018

0 Stimmen

t=0;
theta0=pi/3; %error was NOT here
L=.5;
lam=6;
for n=1:161
t(n+1) =t(n)+.02; theta(n)=theta0*sin(lam*t(n));
omega(n)=lam*theta0*cos(lam*t(n)); alpha(n)=-lam^2*theta(n);
xA(n)=t(n);
yA(n)=t(n)^(3)/18;
xB(n)=xA(n)+L*sin(theta(n));
yB(n)=yA(n)-L*cos(theta(n));
uA(n)=1;
vA(n)=t(n)^(2)/6;
uB(n)=uA(n)+L*omega(n)*cos(theta(n));
vB(n)=vA(n)+L*omega(n)*sin(theta(n));
axA(n)=0;
ayA(n)=t(n)/3;
axB(n)=L*alpha(n)*cos(theta(n))-L*omega(n)^2*sin(theta(n));
ayB(n)=ayA(n)+L*alpha(n)*sin(theta(n))+L*omega(n)^2*cos(theta(n));
end;
line(xA, xB,'r') %error was here
hold on
line(yA,yB','g') %error was here

5 Kommentare

Maria Shehadeh
Maria Shehadeh am 3 Nov. 2018
It was the pi/3 in the end. thank you!
madhan ravi
madhan ravi am 3 Nov. 2018
Anytime :)
No, pi is a function and using pi() /3 is legal.
The problem is that
line([xA(n) xB(n)]),[yA(n) yB(n)]);
has an extra ) after the first]
madhan ravi
madhan ravi am 3 Nov. 2018
Ah thank you sir Walter didn’t notice it because the question was edited at the beginning until you did
Maria Shehadeh
Maria Shehadeh am 3 Nov. 2018
Just caught that didn't realize I retyped it properly in the end. Thanks!

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