conv2 'valid' implementation
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I need to implement the conv2 function for a the HDL coder since it's not supported, I believe that I have the main function down, what I'm struggling with is the implementation of conv2 'valid' which is described in the documentation with — Returns only parts of the convolution that are computed without zero-padded edges-
The code for conv2 is the one I'm sharing, any help would be appreciated.
function B = convolve(A, k)
[r, c] = size(A);
[m, n] = size(k);
h = rot90(k, 2);
center = floor((size(h)+1)/2);
left = center(2) - 1;
right = n - center(2);
top = center(1) - 1;
bottom = m - center(1);
Rep = zeros(r + top + bottom, c + left + right);
for x = 1 + top : r + top
for y = 1 + left : c + left
Rep(x,y) = A(x - top, y - left);
end
end
B = zeros(r , c);
for x = 1 : r
for y = 1 : c
for i = 1 : m
for j = 1 : n
q = x - 1;
w = y -1;
B(x, y) = B(x, y) + (Rep(i + q, j + w) * h(i, j));
end
end
end
end
2 Kommentare
Juan Pereira
am 7 Okt. 2019
Useful, thank you.
Savannah Quinn
am 13 Sep. 2020
Hello, I am trying to use this code to implement various image filters however I keep getting the an index out of bounds error due to h(i,j). Any ideas?
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Bharath Venkataraman
am 2 Nov. 2018
Bearbeitet: Bharath Venkataraman
am 2 Nov. 2018
0 Stimmen
If you are looking for conv2 for image filtering, you can use the ImageFilter block and System object in Vision HDL Toolbox.
1 Kommentar
Bharath Venkataraman
am 20 Nov. 2018
0 Stimmen
2 Kommentare
Alla
am 29 Nov. 2018
Bharath Venkataraman
am 29 Nov. 2018
conv2 with 'valid' returns a smaller image (without padding), so please make sure you are only comparing the central part of the image.
You may find it closer to matching if you use 'same' instead of 'valid'.
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