Sum through an array until a value is reached, then continue
Ältere Kommentare anzeigen
Assume you have 2 arrays x = linspace(0.001,0.005,1000); y = linspace(0,1,1000);
I want to start at the beginning of x, and sum consecutive columns until the sum = 0.1, then take the average of y across that range.... then continue doing this until the end of x
6 Kommentare
madhan ravi
am 2 Nov. 2018
give a short example of your desired result
Bruno Luong
am 2 Nov. 2018
Description inaccurate and contradictory.
It looks like the "cumulative sum" is actually y (100 elements).
x never reaches 0.1.
Cumulative sum on x and y never give 0.1 crossing at 100 elements.
Bruno Luong
am 2 Nov. 2018
Bearbeitet: Bruno Luong
am 2 Nov. 2018
"With the values given, the first 100 columns would sum to 0.1"
No body know where the 100 comes from. Anyone is guessing and people just wastes theirs times for you.
Not give example is better than give one that doesn't make sense.
Anthony
am 2 Nov. 2018
Akzeptierte Antwort
Weitere Antworten (2)
madhan ravi
am 2 Nov. 2018
Bearbeitet: madhan ravi
am 2 Nov. 2018
mean(y(cumsum(x)<=0.1))
8 Kommentare
Anthony
am 2 Nov. 2018
madhan ravi
am 2 Nov. 2018
see the edited answer
Anthony
am 2 Nov. 2018
madhan ravi
am 2 Nov. 2018
did you read Brunos comment?
Guillaume
am 2 Nov. 2018
In case you haven't noticed you were given another answer that matches your description.
"this deosn't produce a correct output" is totally useless if you don't tell us what the correct output is. Vagues descriptions that don't actually match the example you've given doesn't cut it.
As has been pointed out, your statement "the first 100 columns would sum to 0.1" is incorrect. cumsum(x) reaches 0.1 at column 86.
Anthony
am 2 Nov. 2018
Bruno Luong
am 2 Nov. 2018
Yes 1 over 4 people figures it out ...by chance.
Anthony
am 2 Nov. 2018
Guillaume
am 2 Nov. 2018
sumx = cumsum(x);
meanybelowthreshold = mean(y(sumx <= 0.1));
meanyabovethreshold = mean(y(sumx > 0.1));
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!