Following code is coming up with error "Array indices must be positive integers or logical values."
Does someone know what is causing this. Trying to store each value into an array
z =@(x) tan(x);
h = 0.5
for x=1:0.5:10
Output (x) = (z(x+h)-z(x-h))/(2*h);
end
Array = [Output]

1 Kommentar

Stephen23
Stephen23 am 25 Okt. 2018
Bearbeitet: Stephen23 am 25 Okt. 2018
Note that your code can be trivially vectorized (a loop is a waste of time):
z = @tan;
h = 0.5;
x = 1:0.5:10;
y = (z(x+h)-z(x-h))./(2*h);
Learn how to write neat and efficient MATLAB code:

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madhan ravi
madhan ravi am 25 Okt. 2018
Bearbeitet: madhan ravi am 25 Okt. 2018

0 Stimmen

z =@(x) tan(x);
h = 0.5
x=1:0.5:10
Output = zeros(1,19) %preallocation for speed and efficiency
for i = 1:numel(x)
Output (i) = (z(x(i)+h)-z(x(i)-h))/(2*h);
end
Array = Output

3 Kommentare

madhan ravi
madhan ravi am 25 Okt. 2018
you can access x(1.5)->(second iteration) because indexing should be real integers
Stephen23
Stephen23 am 25 Okt. 2018
@madhan ravi: where is the array preallocation? What do those square brackets do? (Hint: nothing)
madhan ravi
madhan ravi am 25 Okt. 2018
Thank you Stephen (edited now)

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