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Is there a way to index a variable to a certain position in the array

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I have some code that looks like this:
if n==1
for i=1:size(ob,1)
rt(i,:,:)=radon(squeeze(ob(i,:,:)),ra);
end
elseif n==2
for i=1:size(ob,2)
rt(i,:,:)=radon(squeeze(ob(:,i,:)),ra);
end
elseif n==3
for i=1:size(ob,3)
rt(i,:,:)=radon(squeeze(ob(:,:,i)),ra);
end
end
Is there a way to get the i variable to the nth position of the ob matrix so that I don't have to write an if statement for each n?

Accepted Answer

Fangjun Jiang
Fangjun Jiang on 23 Oct 2018
Depending on the value of n, you want to loop through the different dimension of matrix.
I think you can utilize the function shiftdim() to pre-process you matrix and then do the same loop, something like
shiftdim(ob,n)

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More Answers (1)

Jose Sanchez
Jose Sanchez on 23 Oct 2018
This should work:
n=3; % or set n=1 or n=2
tmp = permute(ob, [setdiff(1:3,n) n]);
for i=1:size(tmp,3)
rt(i,:,:) = radon(tmp(:,:,i),ra);
end

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