Convert this C program into a Matlab program.
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ex[1]=lx/J %%first i term in ex matrix
ex[2]=mx/J %%second j term in ex matrix
ex[3]=nx/J %%third k term in ex matrix
for (i=0;i<9;i++)
for (j=0;i<27;j++)
N_matrix[i,j]=0;
end
for (i=0;i<9;i++)
N_matrix(0,i)=N[i%3]*ex[i/3];
end
4 Kommentare
Jan
am 16 Okt. 2018
Bearbeitet: Jan
am 16 Okt. 2018
@Virajan Verma: You are not a newbie in this forum. I've formatted the code for your today, but please mark the code with the mouse and press the "{} Code" button by your own in the future. Thanks.
This is not C code, because there is no "end" in C. What is N? Are you sure that you want to insert values in the first row, not column?
Guillaume
am 16 Okt. 2018
N_matrix(0,i) is also not correct C syntax. The brackets should be square.
And as Jan pointed out, it should probably be:
N_matrix[i,0]
Antworten (1)
Jan
am 16 Okt. 2018
ex = [lx; mx; nx] / J;
N = rand(3, 1); % ???
N_matrix = zeros(9, 27);
N_matrix(1, 1:9) = repmat(N, 3, 1) .* repelem(ex, 3, 1)
4 Kommentare
Walter Roberson
am 18 Okt. 2018
That code creates a row vector for N, not a column vector. Try N(1,1), N(2,1), N(3,1) as the destinations
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