How to plot four variables in a line graph ?

I have one equation with 4 variables (x,y,z,d).I substitute the variable x in the equation and have 3 variables. I want to plot with 3 variables in a line graph.
How can I plot this graph? Thank you very much for your answer :)

6 Kommentare

KSSV
KSSV am 8 Okt. 2018
Show us the equation....I guess there would be some range to other variables as well i.e for (x,y,z)
chayanon summueang
chayanon summueang am 8 Okt. 2018
Bearbeitet: chayanon summueang am 8 Okt. 2018
I have 4 varaibles (x4,y4,z4,d) and substitute x4 in equation of volume numerical intergration (UU).I want to plot potential and range of varaible d in a line plot.Thank for help :)
KSSV
KSSV am 8 Okt. 2018
Copy the code....no image snippets.....
chayanon summueang
chayanon summueang am 8 Okt. 2018
Bearbeitet: KSSV am 8 Okt. 2018
% range of varaibles (x4,y4,z4)
x4 = 2.1*(10^-9);
y4 = -8*(10^-9):1*(10^-9):8*(10^-9);
z4 = -8*(10^-9):1*(10^-9):8*(10^-9);
% range of varaible d
d = 2*(10^-9):1*(10^-9):5*(10^-9);
% Volume integration
Vx3d = -2*(10^-9);
Vx3t = 2*(10^-9);
Vy3d = -2*(10^-9);
Vy3t = 2*(10^-9);
Vz3d = 0;
Vz3t = 4*(10^-9);
% Numerical integration
Potential = zeros(length(y4),length(z4),length(d));
for i1 = 1:length(y4)
for j1 = 1:length(z4)
for k1 = 1:length(d)
Potential(i1,j1,k1) = integral3(@(x1,y1,z1) UU(d(k1),x1,x4,y1,y4(j1),z1,z4(i1)),Vx3d,Vx3t,Vy3d,Vy3t,Vz3d,Vz3t) ;
end
end
end
Jan
Jan am 8 Okt. 2018
@chayanon summueang: By the way, the code looks much nicer, if you replace the expensive power operation 1*(10^-9) by the fast constant 1e-9. In addition you can use the "{} Code" button instead of inserting a blank line after each line of code.
You forgot to mention the problem you have with this code.
madhan ravi
madhan ravi am 8 Okt. 2018
Btw no of elements of x4 y4 are not the same.

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