How to replace matrix value with string from cell array?
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Johnny Birch
am 1 Okt. 2018
Kommentiert: Johnny Birch
am 2 Okt. 2018
I have a cell array of string and a data matrix. How do I replace the value in the data matrix with the strings marked by ‘#’. I want the output to be a cell array of strings like the “output” in the script below.
cell = {
'# 2.537' '1.219' '0.457' '0.214' '# 0.120' '0.245'
'3.244' '# 1.400' '0.649' '0.515' '0.207' '0.075'
'2.993' '1.282' '0.605' '0.309' '0.140' '0.140'
'3.278' '1.507' '0.885' '0.405' '0.160' '0.111'
'3.691' '1.474' '0.650' '0.316' '0.180' '0.155'}
data=[
0.8147 0.0975 0.1576 0.1419 0.6557 0.7577
0.9058 0.2785 0.9706 0.4218 0.0357 0.7431
0.1270 0.5469 0.9572 0.9157 0.8491 0.3922
0.9134 0.9575 0.4854 0.7922 0.9340 0.6555
0.6324 0.9649 0.8003 0.9595 0.6787 0.1712]
output={
'# 2.537' '0.0975' '0.1576' '0.1419' '# 0.120' '0.7577'
'0.9058' '# 1.400' '0.9706' '0.4218' '0.0357' '0.7431'
'0.1270' '0.5469' '0.9572' '0.9157' '0.8491' '0.3922'
'0.9134' '0.9575' '0.4854' '0.7922' '0.9340' '0.6555'
'0.6324' '0.9649' '0.8003' '0.9595' '0.6787' '0.1712'}
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Akzeptierte Antwort
Jan
am 2 Okt. 2018
output = sprintfc('%.4f', data);
index = strncmp(c, '#', 1);
output(index) = c(index);
Weitere Antworten (1)
jonas
am 1 Okt. 2018
Bearbeitet: jonas
am 1 Okt. 2018
Cell is a built in function so avoid using it as a variable name. Anyway, you can try this:
mask=logical(count(cell,'#'))
data=cellstr(string(a))
data(mask)=cell(mask)
data =
5×6 cell array
{'# 2.537'} {'0.0975' } {'0.1576'} {'0.1419'} {'# 0.120'} {'0.7577'}
{'0.9058' } {'# 1.400'} {'0.9706'} {'0.4218'} {'0.0357' } {'0.7431'}
{'0.127' } {'0.5469' } {'0.9572'} {'0.9157'} {'0.8491' } {'0.3922'}
{'0.9134' } {'0.9575' } {'0.4854'} {'0.7922'} {'0.934' } {'0.6555'}
{'0.6324' } {'0.9649' } {'0.8003'} {'0.9595'} {'0.6787' } {'0.1712'}
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