Why is exist(variable,'var') not seeing a variable?

25 Ansichten (letzte 30 Tage)
Bogdan Dzyubak
Bogdan Dzyubak am 24 Sep. 2018
Beantwortet: Steven Lord am 24 Sep. 2018
I have a function to which a variable is passed. The variable exists:
'signedOrNot = signed'
When I call 'exist signedOrNot var' it is found:
ans = 1
But when I use exist(signedOrNot,'var'), as I would in an if statement, it is not:
ans = 0
Any thoughts?

Akzeptierte Antwort

Fangjun Jiang
Fangjun Jiang am 24 Sep. 2018
exist('signedOrNot','var')

Weitere Antworten (1)

Steven Lord
Steven Lord am 24 Sep. 2018
This line of code tests whether the variable with the name signedOrNot exists in the workspace.
exist('signedOrNot', 'var')
This line of code tests whether the variable whose name is stored in the variable signedOrNot exists in the workspace.
exist(signedOrNot, 'var')
Compare:
% if a variable by this name exists, choose a different name
signedOrNot = 'thisVariableShouldNotExist';
passingName = exist('signedOrNot', 'var') % true, signedOrNot exists
passingContentsOfVariable = exist(signedOrNot, 'var') % false, thisVariableShouldNotExist doesn't
with:
x = 42;
signedOrNot = 'x';
passingName = exist('signedOrNot', 'var') % true, signedOrNot exists
passingContentsOfVariable = exist(signedOrNot, 'var') % true, x exists

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