Typecasting a matrix of 200x8 uint8 to double

I am typecasting data from uint8 to double so I am using typecast function. I have matrix of 200x8 uint8 which want to convert it into double. So if I use a for loop like below.

if true
  convert_double = [];                                                                                                                  
  a = [200x8];
  for i =1:200
       convert_double = [convert_double; typecast(uint8(a(i,:)), 'double')];
  end
end

But I want to remove this for loop so that in one instance itself I will get 200x1 double data

Answer 1

[Guillaume]

Transpose your a before reshaping into a vector:

convert_double = typecast(reshape(uint8(a'), 1, []), 'double')

Answer 2

[Christopher Wallace]

double(a);

[Guillaume]

There is a big difference between plain conversion with double and casting with typecast. Compare

 a = uint8([154, 8, 27, 158, 94, 41, 240, 63])

 double(a)
 typecast(a, 'double')

[Christopher Wallace]

Absolutely, depends on what the author wants to do with the data. After seeing your answer I see what the "200x1 double data" portion was aiming at.