how to reverse a random permutation of a matrix to get back the original matrix?
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shashwat soni
am 17 Sep. 2018
Kommentiert: shuaib ahmed
am 13 Jun. 2019
O = key1(randperm(numel(key1)));
here O is the random permutation of rows and columns of a 'key1' matrix which is '16*147'. how to get back my original key1 matrix?
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Andrei Bobrov
am 17 Sep. 2018
key1 = randi(398,4,5);
s = size(key1);
p = reshape(randperm(numel(key1)),s);
O = key1(p);
[~,ii] = sort(p(:));
out = O(reshape(ii,s));
1 Kommentar
Bruno Luong
am 17 Sep. 2018
Bearbeitet: Bruno Luong
am 17 Sep. 2018
alternatively one can do indexing on the lhs and avoid sorting
out(p) = O;
out = reshape(out,s);
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Image Analyst
am 17 Sep. 2018
See attached demo.

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Image Analyst
am 17 Sep. 2018
My code would give 16*49 numbers, which would keep each pixel together. In other words, the green and blue values move to the same location as the red value. This has the effect of simply shuffling the pixels to new locations while keeping the color of the pixel the same (because red, green, and blue all move together to the same new location).
I'm not sure if you want 3 values for each row, or if you want 3 values for each pixel - you seemed to say/indicate both. If you wanted 3 values for each row, I'm not sure how that would look. If you wanted 3 values for each pixel then you could be moving the red, green, and blue values to different locations. To do that with my code you'd simply get 3 sort orders, one for each color channel:
% Get the orders to scramble them in.
scrambleOrderR = randperm(rows*columns);
scrambleOrderG = randperm(rows*columns);
scrambleOrderB = randperm(rows*columns);
% Scramble according to the scrambling order for each individual color channel.
redChannel = redChannel(scrambleOrderR);
greenChannel = greenChannel(scrambleOrderG);
blueChannel = blueChannel(scrambleOrderB);
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