I am working with Matlab to reproduce SAR image by radar. But when I calculate the EXP function, the result is so different.
>> exp(0.000000000000000e+00 - 8.378507193591911e+06i)
ans =
0.5122 + 0.8588i
>> exp(0.000000000000000e+00 - 8.378522834360446e+06i)
ans =
-0.4534 - 0.8913i
I do not know why in the result, one is negative, and one is positive. Please help me with this. Thank you so much for your consideration.

3 Kommentare

Torsten
Torsten am 3 Sep. 2018
exp(it) = cos(t)+i*sin(t)
So why are you surprised about the result ?
Best wishes
Torsten.
Stephen23
Stephen23 am 3 Sep. 2018
Bearbeitet: Stephen23 am 3 Sep. 2018
There is nothing surprising about those results, their difference is more than 2*pi:
>> L = 8.378507193591911e+06;
>> R = 8.378522834360446e+06;
>> R-L
ans = 15.641
You can plot this easily, and see how that range includes real and imaginary parts that are both positive and negative:
>> V = linspace(L,R,100);
>> E = exp(complex(0,V));
>> plot(E,'-*')
>> M = [real(E(:)),imag(E(:))];
>> plot(V,M,'-*')
Nguyen Trung Kien
Nguyen Trung Kien am 4 Sep. 2018
Thank you so much for your comments. I understood that everything is normal and my question is weird so I had closed it. Many thanks for your explanations.

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

madhan ravi
madhan ravi am 3 Sep. 2018

0 Stimmen

I tried and got the same result too even the result in Wolfram is the same.

4 Kommentare

Nguyen Trung Kien
Nguyen Trung Kien am 3 Sep. 2018
Because if I continue using this result for Fast Fourier Transform, the final result will become wrong. So do you have any suggestion for me in this situation?
madhan ravi
madhan ravi am 3 Sep. 2018
Bearbeitet: madhan ravi am 3 Sep. 2018
No there is nothing wrong with both the answers. You can also verify the results in other appilications they give the same answers as the above.Even if you paste the expressing in google the answers you get are the same!
Nguyen Trung Kien
Nguyen Trung Kien am 3 Sep. 2018
I have just tried with excel, and same as your attention. Thank you so much. I think I will close this question.
madhan ravi
madhan ravi am 4 Sep. 2018
Your welcome and don’t close the question.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Produkte

Version

R2017b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by