my goal is to obtain a matrix A (2x2) using a function called somma:
function [] =somma (x,y)
z=x+y
my script code is :
clear all
clc
x=1:2;
y=3:4;
A=zeros(length(x),length(y));
[x1,x2]=meshgrid(x,y);
for i=1:length(x);
for j=1:length(y);
A(i,j)=somma(x1(i,j),x2(i,j));
end
end
A
the error reported is:
Error using somma
Too many output arguments.
Error in untitled5 (line 9)
A(i,j)=somma(x1,x2);

 Akzeptierte Antwort

Image Analyst
Image Analyst am 2 Sep. 2018

0 Stimmen

You forgot to have somma return any value! Have it return z and it will work:
clc
x=1:2;
y=3:4;
A=zeros(length(x),length(y));
[x1,x2]=meshgrid(x,y)
for i = 1 : length(x)
for j = 1 : length(y)
A(i,j) = somma(x1(i,j), x2(i,j));
end
end
A
function [z] =somma (x,y)
z = x + y
end

2 Kommentare

now my script code is:
clear all
clc
x=1:2;
y=3:4;
A=zeros(length(x),length(y));
[x1,x2]=meshgrid(x,y);
for i=1:length(x)
for j=1:length(y)
A(i,j)=somma(x1(i,j),x2(i,j))
end
end
A
function [z] =somma (x,y)
z = x + y
end
my function code is:
function [z]=somma(x,y)
z=x+y;
end
errore reported :
Error: File: untitled5.m Line: 15 Column: 1
Function definitions are not permitted in this
context.
Walter Roberson
Walter Roberson am 2 Sep. 2018
Store the code for the function in a separate file. Having a function in a script file requires R2016b or later.

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Weitere Antworten (2)

ahmed nebli
ahmed nebli am 2 Sep. 2018

0 Stimmen

when writing the for loop it dosen't end with a ; and next the second for loop need to be under the first for loop and decaled by one tab, see syntax in this example https://www.mathworks.com/help/matlab/ref/for.html

1 Kommentar

same error message with this code:
clear all
clc
x=1:2;
y=3:4;
A=zeros(length(x),length(y));
[x1,x2]=meshgrid(x,y);
for i=1:length(x)
for j=1:length(y)
A(i,j)=somma(x1(i,j),x2(i,j));
end
end
A

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Marco Barbarossa
Marco Barbarossa am 3 Sep. 2018

0 Stimmen

thanks to all! Walter Roberson is right !

1 Kommentar

Image Analyst
Image Analyst am 3 Sep. 2018
Or, better if you can, upgrade your release to the latest version.

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