How can I find the distance between different dimensional matrices?

Hello

When I extract minutiae of fingerprints, their number is different between one image and another. after preprocessing make thin to ridges

 im = bwmorph(im,'thin',Inf);

 % now clean up the thin image

 im = bwmorph(im,'clean');       % Removes single isolated pixels

 im = bwmorph(im,'hbreak');    % Removes H-Breaks 
  
 newim = bwmorph(im,'spur');     % Removes spikes

Minutiae is extracted by morphological processes Minutiae is the end points and branches However, due to the difference in the quality of the images and other reasons like different fingerprint size Although the size of the image is fixed, or part of the fingerprint is broken. The features obtained will vary between one image and another, these features are points (x, y and orientation(o)), every fingerprint is represented by a matrix of these features,

How can I find the distance between different dimensional matrices?

thank you

[Adam Danz]

If you provide a MWE it would be helpful.

[wisam kh]

Thank you for this interaction I will see it

[wisam kh]

I could not find what I was looking for

[Walter Roberson]

In other words, you should post some code and data.

[Walter Roberson]

What are the factors that lead to different dimensions? Are you not automatically cropping and resizing what is left to a constant size?

[wisam kh]

Well I will add the details

Answer 1

[Walter Roberson]

"How can I find the distance between different dimensional matrices?"

You cannot do that; it has no mathematical meaning.

You will need to find a different approach.

[wisam kh]

Do you have any suggestion?

[Walter Roberson]

Fingerprint analysis is not something I have studied.

I would tend to think that one approach would be to use image registration to align the images, and then to extract minutae from both, find locations in common, and compare. I do not know if this approach is practical.

I would suggest that you examine scientific papers on fingerprint analysis, such as at http://scholar.google.com

[wisam kh]

Thank you I appreciate your effort