Replace elements in matrix based on indices stored in another matrix
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LM_BU
am 31 Jul. 2018
Kommentiert: Star Strider
am 31 Jul. 2018
I will probably be unable to articulate the problem well.
There are three variables, indicating indices:
a = [3:10, 17:21, 28]; b = [11:13, 22:24, 29:30]; c = [14:16, 25:27];
These are all indices in a categorical fashion (each variable is a category). Now, I want to create a variable to feed into a RepeatedMeasuresModel; hence, I will need some sort of dummy coding. To automate this, I want to have a matrix whose elements are 1, 2 or 3 (thereby representing a/b/c), based on the indices from the said variables.
E.g. conditions = [1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 1, 1, ...., 2, 2]; %n = 30. How do I output this? I have tried logical indexing, but it fails, because the matrices are not the same size. E.g. conditions = 1:30; conditions(conditions==a) = 1;
A side question, how would I, instead of say using 1/2/3 integers, use char arrays instead? For instance, instead of 1, we want to place the "value" 'Category1', 2 = 'Category 2', etc.
Thanks for your support.
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Star Strider
am 31 Jul. 2018
I am not exactly certain what you want.
Try this:
a = [3:10, 17:21, 28];
b = [11:13, 22:24, 29:30];
c = [14:16, 25:27];
conditions = zeros(1,30); % Preallocate
conditions(a) = 1;
conditions(b) = 2;
conditions(c) = 3
cats = cell(1,30); % Preallocate
cats(a) = {'Category1'};
cats(b) = {'Category2'};
cats(c) = {'Category3'}
conditions =
' 0 0 1 1 1 1 1 1 1 1 2 2 2 3 3 3 1 1 1 1 1 2 2 2 3 3 3 1 2 2 '
cats =
' Category1 Category1 Category1 Category1 Category1 Category1 Category1 Category1 Category2 Category2 Category2 Category3 Category3 Category3 Category1 Category1 Category1 Category1 Category1 Category2 Category2 Category2 Category3 Category3 Category3 Category1 Category2 Category2 '
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