Return subscripts of common rows for multi-dimensional matrix?
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Andrew Poissant
am 13 Jul. 2018
Kommentiert: dpb
am 13 Jul. 2018
I have a 8x2 matrix, A, and a 133x2x5 matrix, B. I want to return the the layer in B in which a row in A matches a row in B. How can I do that? I tried using intersect and ismember but have not had any luck thus far. Having a hard time with the matrix being multi-dimensional.
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Guillaume
am 13 Jul. 2018
And you don't care about which is the row in B that match a A row in that layer?
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Guillaume
am 13 Jul. 2018
Bearbeitet: Guillaume
am 13 Jul. 2018
[row, layer] = ind2sub([size(B, 1), size(B, 3)], find(ismember(reshape(permute(B, [1 3 2]), [], size(B, 2)), A, 'rows')))
If you want just the layers in which any row matches any row of A:
layer = unique(layer)
edit: By the way the logic of this is to reshape B into a two column matrix by vertically concatenating the layers. Then use the traditional ismember(..., 'rows') and finally convert the matched rows back into (row, layer) coordinate.
Another way, avoiding the sub2ind would be:
layer = unique(ceil(find(ismember(reshape(permute(B, [1 3 2]), [], size(B, 2)), A, 'rows')) / size(B, 1)))
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