how do i get the last points of every 100 points from a 1000 point graph

x=0:1000
y=sin(x)
for N=0:100:length(x)
    if N>N-50
        N
    end
end

this is what i have and i know its not right so please help

[per isakson]

>> x((0:100:1000)+1)
ans =
           0         100         200         300         400         500         600         700         800         900        1000

[per isakson]

I converted your answer to a comment

x=0:100:1000;
y=sin(x)

By this way you just get the datas after every 100th term.

[per isakson]

Indeed, so what do you want?

[Image Analyst]

Huh? Is Carlos deleting his responses? All I see is this:

"how do i get the last points of every 100 points from a 1000 point graph"

x=0:1000
y=sin(x)
for N=0:100:length(x)
    if N>N-50
        N
    end
end

Which is very confusing in itself.

Answer 1

[per isakson]

"how do i get the last points of every [sequence of] 100 points from a [sequence of] 1000 point[s]" That's my interpretation of your question.

What about

>> x((100:100:1000))
ans =
    99   199   299   399   499   599   699   799   899   999
>> y((100:100:1000))
ans =
   -0.9992   -0.8818   -0.5216   -0.0177    0.4910    0.8645    1.0000    0.8601    0.4834   -0.0265
>>

Notice

>> length(x)
ans =
        1001

[Carlos Nunez]

yea this works thanks