Hello,
I have the following for loop, where pairs(500x10), is there to calculate cc without for loop?
for i=1:500
cc(i,:)=pairs(i,pairs(i,:));
end

4 Kommentare

Stephen23
Stephen23 am 2 Jul. 2018
@Mantas Vaitonis: what is pairs2 ? What values do pair and pairs2 contain?
Mantas Vaitonis
Mantas Vaitonis am 2 Jul. 2018
Bearbeitet: Mantas Vaitonis am 2 Jul. 2018
Sorry, tehre was mistake, both are pairs, they contain double type values like [1 5 4 3 5].
@Mantas Vaitonis: given that pairs contains non-integer values, what do you expect
pairs(i,pairs(i,:));
to do?
Mantas Vaitonis
Mantas Vaitonis am 2 Jul. 2018
Those values suppose to be integer, i fixed my commnet, and should return valuse by index stored in pairs.

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

Jan
Jan am 2 Jul. 2018
Bearbeitet: Jan am 2 Jul. 2018

0 Stimmen

s = size(pairs);
index = sub2ind(s, repmat((1:s(1)).', 1, s(2)), pairs)
cc = pairs(index)

3 Kommentare

Mantas Vaitonis
Mantas Vaitonis am 2 Jul. 2018
Unfortunately, it is not what I am looking for. With Your code if I have pairs [5 1 4 5 1], cc should be [1 5 5 1 5] and the result with your code is [4 5 2 4 5].
Jan
Jan am 2 Jul. 2018
Bearbeitet: Jan am 2 Jul. 2018
pairs = [5 1 4 5 1];
s = size(pairs);
index = sub2ind(s, repmat((1:s(1)).', 1, s(2)), pairs)
cc = pairs(index)
cc =
1 5 5 1 5
I don't know why you get [4 5 2 4 5]. Please try it again.
Mantas Vaitonis
Mantas Vaitonis am 2 Jul. 2018
Maybe I did mistake when copying your code, now it did work, thank you.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Hilfe-Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by