How can i reorder NxM matrix into a 1D array

I am looking to take a sample matrix below. The matrix will be large and looking for fast and non looping solution. Thank you.

a=[1 2 3;4 5 6;7 8 9];

reshape it into:

b=[7 8 9 4 5 6 1 2 3];

[Matthew]

No the matrix is not always 3 rows. It will likely be much more in both rows and columns.

Answer 1

[Star Strider]

Using the reshape (link) function:

b = reshape(a([3 2 1],:)', 1, [])

b =
     7     8     9     4     5     6     1     2     3

[Stephen23]

Or generalized for any number of rows:

reshape(a(end:-1:1,:).', 1, [])

Answer 2

[Alfonso]

Without looping you can do:

b = [a(end,:), a(end-1,:), a(end-2,:)]; % 1D array
b =

     7     8     9     4     5     6     1     2     3

You can repeat the iterations as many rows you have: [a(end-1,:), ... ,a(end-50,:)]