How to Concatenate struct arrays efficiently
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Kenneth Yesh
am 24 Mai 2018
Kommentiert: Kenneth Yesh
am 25 Mai 2018
I use parallel processing to run roughly 35,000 jobs in parallel. They output a .mat file and I want to concatenate them into one big file.
The process takes too long to run. (I am waiting for it to run while writing this) Is there a more optimal way to concatenate struct arrays so this doesn't take hours to run?
I'm guess the the limiting factor is reallocating "finalData".
Note: outData is a struct array of n elements
inputs = dir([intputDir,filesep,'*.mat']);
finalData = [];
if ~exist([outputDir],'dir')
mkdir([outputDir]);
end
l=length(inputs);
for i = 1:l
load([inputs(i).folder,filesep,inputs(i).name]);
finalData = [finalData,outData];
if (mod(i,100) == 0)
fprintf('Finished .Mat File # %d of %d',i,l);
end
end
save([outputDir,filesep,'allOutputs'],'finalData');
struct2xls(finalData,[outputDir,filesep,'Timing_Analysis_Data.xlsx']);
2 Kommentare
James Tursa
am 24 Mai 2018
Bearbeitet: James Tursa
am 24 Mai 2018
Load into variables inside the loop, and then concatenate all of the variables after the loop. Rough outline:
c = cell(l,1);
for i = 1:l
c{i} = load([inputs(i).folder,filesep,inputs(i).name]);
if (mod(i,100) == 0)
fprintf('Finished .Mat File # %d of %d',i,l);
end
end
% then concatenate all of the c{:} here
Do all of your individual struct arrays have the same fields?
Akzeptierte Antwort
Stephen23
am 25 Mai 2018
Bearbeitet: Stephen23
am 25 Mai 2018
Your very slow code is due to that your variable finalData changes size on every loop iteration, forcing MATLAB to move it in memory. Read this to know more:
D = dir(fullfile(inputDir,'*.mat'));
N = 1:numel(D);
S = struct('outData',cell(N,1));
for k = 1:N
F = fullfile(inputDir,D(k).name);
S(k) = load(F,'outData');
end
Data = [S.outData];
save('newfile.mat','Data')
Note it is recommended to use fullfile rather than fiddling around with file separators and string concatenation.
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