I have n*n matrix.I want to get all the elements of 1st column of nth rows like A(:,1). Now how will i arrange all the n elements into a single row i,e b=[A(1,1) A(2,1) A(3,1)............ A(n,1)].What will be the command for n being large say 5000?

3 Ansichten (letzte 30 Tage)
I have n*n matrix.I want to get all the elements of 1st column of nth rows like A(:,1). Now how will i arrange all the n elements into a single row i,e b=[A(1,1) A(2,1) A(3,1)............ A(n,1)].What will be the command for n being large say 5000?

Akzeptierte Antwort

Stephen23
Stephen23 am 14 Mai 2018
Bearbeitet: Stephen23 am 14 Mai 2018
The most general, correct answer is to use transpose .' (rather than conjugate transpose '):
A(:,1).'
  2 Kommentare
phoenix
phoenix am 14 Mai 2018
what is the difference between transpose and conjugate transpose(i.e between A(:,1).'and A(:,1)' ) ?
James Tursa
James Tursa am 14 Mai 2018
Bearbeitet: James Tursa am 14 Mai 2018
If A is real, there is no difference in the result. If A is complex, then ' will conjugate the elements (i.e., negate the imaginary part), whereas .' will not conjugate the elements.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

KSSV
KSSV am 14 Mai 2018
b = A(:,1)' ;

Kategorien

Mehr zu Resizing and Reshaping Matrices finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by