Filter löschen
Filter löschen

How to plot circle by one single equation?

167 Ansichten (letzte 30 Tage)
Ameer Hamza
Ameer Hamza am 13 Mai 2018
Kommentiert: krishan Gopal am 9 Dez. 2021
I need code which plot the circle in one single equation (variable). I have the code but i need code of single equation, the code which i have, it is composed of two equations as follow :
r=2;
x=0;
y=0;
th = 0:pi/6:2*pi;
xunit = r * cos(th) + x;
yunit = r * sin(th) + y;
plot(xunit, yunit);

Akzeptierte Antwort

John D'Errico
John D'Errico am 13 Mai 2018
Bearbeitet: John D'Errico am 13 Mai 2018
As one "equation" what does that mean? About the best I can offer is this:
r=2;
x0=0;
y0=0;
ezplot(@(x,y) (x-x0).^2 + (y-y0).^2 -r^2)
axis equal
Be careful that the units are equal for the two axes, else it ill not look circular.
I could also have done it using fimplicit.
r=2;
x0=0;
y0=0;
syms x y
fimplicit((x-x0).^2 + (y-y0).^2 -r^2)
axis equal
So, in either case, only one equation.
If you really insist on only one "variable, then you need to use a polar coordinate transformation. Thus, you can do it in terms of polar angle theta, as:
r=2;
x0=0;
y0=0;
theta = linspace(0,2*pi,100);
plot(x0 + r*cos(theta),y0 + r*sin(theta),'-')
axis equal
So only one variable, theta. If you are hoping for something else, something more or less, then you need to explain carefully what the goal is here.
Are you looking for a simple way to plot a circle? Perhaps try this:
cplot = @(r,x0,y0) plot(x0 + r*cos(linspace(0,2*pi)),y0 + r*sin(linspace(0,2*pi)),'-')
Now you have a little function that will plot a circle.
cplot(2,0,0)
hold on
cplot(3,1,2)
cplot(1,-1,1)
axis equal
  2 Kommentare
Abdulrahman Saad
Abdulrahman Saad am 5 Okt. 2019
Thank you very much
krishan Gopal
krishan Gopal am 9 Dez. 2021
Hi, can you tell me how to draw line pattern inside the circle

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (3)

Aditya Gupta
Aditya Gupta am 26 Jun. 2020
Adding to the MVP's (perfect) answer, I found one more way:
radius = 2;
originX = 0;
originY = 0;
rectangle('Position',[originX-radius originY-radius 2*radius 2*radius], ...
'Curvature',[1 1]);
axis equal

Harshith pothuri
Harshith pothuri am 14 Jan. 2021
r=2;
x0=0;
y0=0;
theta = linspace(0,2*pi,100);
plot(x0 + r*cos(theta),y0 + r*sin(theta),'-')
axis equal

krishan Gopal
krishan Gopal am 9 Dez. 2021
Hi, can you tell me how to draw line pattern inside the circle

Kategorien

Mehr zu Line Plots finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by