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How can I select particular elements by an increasing step in rows?

3 Ansichten (letzte 30 Tage)
10 20 30
11 21 31
12 22 32
13 23 33
14 24 34
15 25 35
16 26 36
17 27 37
18 28 38
19 29 39
For example: I'd like to extract 4 elements in each column from the matrix above. Extracted elements would be (1,1),(2,1),(3,1),(4,1) for the 1st column, and (1,2),(3,2),(5,1),(7,1) for the 2nd column, and (1,3),(4,3),(7,3),(10,3). Example out is given below:
10 20 30
11 22 33
12 24 36
13 26 39
Note: I have hundreds of rows and columns. So, I need a generic solution.
Thank you.

Akzeptierte Antwort

Stephen23
Stephen23 am 18 Apr. 2018
Bearbeitet: Stephen23 am 18 Apr. 2018

This is easy using linear indexing (a loop is not required):

>> [M(1:10:end);M(2:11:end);M(3:12:end);M(4:13:end)]
ans =
   10   20   30
   11   22   33
   12   24   36
   13   26   39

Note that M has 10 rows, so you can easily adjust the code I gave to work for any number of rows:

>> S = size(M,1);
>> [M(1:S+0:end);M(2:S+1:end);M(3:S+2:end);M(4:S+3:end)]
ans =
   10   20   30
   11   22   33
   12   24   36
   13   26   39

Note that this method only works if the number of columns is <= the number of rows.

To adjust for N elements from each column you can add a loop, either following the method above:

N = 4;
Y = nan(N,size(M,2));
S = size(M,1);
for k = 1:N
    Y(k,:) = M(k:S+k-1:end);
end

or doing a naive implementation of what you explained in your question.

  2 Kommentare
ugur uresin
ugur uresin am 18 Apr. 2018
Dear Stephen,
It might be missed but I need a more ' generic solution' like a for loop since there are hundreds rows and columns in my data.
The matrix that I gave above is just an example.
Sincerely,
ugur uresin
ugur uresin am 18 Apr. 2018
Your edited answer works. Thanks in advance!

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