How to call index of vector from matrix?
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Hello, I have: n-by-3 matrix A, where xi,yi,zi are non-integer(e.g., x=-1.23;y=2.45;z=123.11):
A contain 10million element
A=[ x1 y1 z1 % element 1
x2 y2 z2 % element 2
x3 y3 z3 % element 3
x4 y4 z4 % element 4
.......
xn yn zn] % element n , where n=10,000,000
B=[ x3 y3 z3 % B contain 2 elements
x70 y70 z70]
Question: How to call index of matrix B from matrix A?(i don't wanna use "find(ismember(A,B,'rows'));" , since time consuming with large matrix A & B)
result=[3;70]
1 Kommentar
Image Analyst
am 2 Apr. 2018
I don't know what "call index of matrix" or "call index of vector" means. Perhaps you can get a native English speaker to look it over. And what would you want? Would you want a 2-by-1 vector of rows where the numbers are found? Like output = [3; 70]? Or what??? Or do you want null/empty because row 3 followed by row 70 never ever appear in A?
Antworten (1)
Rik
am 31 Mär. 2018
The code below executes in 0.35 seconds. This will scale about linearly with the number of rows in B.
%Generate data
A=rand(10000000,3);
B=A([3 70],:);
tic
%loop through B to find row indices
result=NaN(size(B,1),1);
for n=1:length(result)
true_row=...
A(:,1)==B(n,1) & ...
A(:,2)==B(n,2) & ...
A(:,3)==B(n,3);
row_idx=find(true_row);
if numel(row_idx)==0
%row not found, keep NaN
elseif numel(row_idx)>1
%more than 1 row found, throw warning
warning('no unique match for row')
%you can use the line below as well, if you just want to use the
%first row that matches.
%result(n)=row_idx(1);
else
result(n)=row_idx;
end
end
toc
3 Kommentare
Rik
am 2 Apr. 2018
Comparing many elements just is very time consuming. Use the profiler or tic and toc to figure out which method is fastest for you application. I don't think there are many ways to improve beyond ismember or the method I outline here. You might check to see if arrayfun or parfor yield any speedup.
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