how can i plot 5 periods of this signal
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hi, i have the following signal and i want to plot 5 cycles of it. but i'm getting an error
samples = 500;
T = 5;
f0 = 1/T;
t = linspace(0,T,samples+1); % 5 cycles
t(end) = [];
s2_hinf = exp(-((t-6)/4));
s2 = repmat(s2_hinf, [1 5]);
figure(1)
plot(t, s2);
but i'm getting the following error Error using plot Vectors must be the same length.
2 Kommentare
Jan
am 25 Mär. 2018
Bearbeitet: Jan
am 25 Mär. 2018
@OMAR ALQARNI: Please do not remove the relevant part of the question. Thanks.
Did you do this, because this is a homework and you do not want it to be found? Remember that the original version is stored in e.g. Google's cache. In addition, you did not let the forum solve your homework, but showed your own effort and asked a specific question. This is not cheating. Communicating with other programmers is a useful strategy to learn programming.
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Jan
am 24 Mär. 2018
Bearbeitet: Jan
am 24 Mär. 2018
If you use repmat to concatenate the data 5 times, you have to concatenate the time t also 5 times, but add T in each block cumulatively:
samples = 500;
T = 5;
t = linspace(0,T,samples+1); % 5 cycles
t(end) = [];
s2_hinf = exp((6 - t) / 4);
s2 = repmat(s2_hinf, [1 5]);
t2 = reshape(t(:) + (0:T:4*T), 1, []); % >= Matlab R2016b
figure;
plot(t2, s2);
With older Matlab versions:
t2 = reshape(bsxfun(@plus, t(:), 0:T:4*T), 1, []);
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Weitere Antworten (2)
Image Analyst
am 24 Mär. 2018
Your linspace() is wrong. You could do this:
samples = 500;
T = 5; % Period
f0 = 1/T; % Not used!
t = linspace(0, 5 * T, samples); % 5 cycles
s2_hinf = exp(-((t-6)/4));
plot(t, s2_hinf);
But I don't see where any cycles comes in. You are not using anything like sin() or cos(), so are you expecting oscillations?
0 Kommentare
Image Analyst
am 24 Mär. 2018
Perhaps you mean this:
samples = 500;
T = 5; % Period
f0 = 1/T; % Not used!
t = linspace(0, T, samples); % 5 cycles
s2_hinf = exp(-((t-6)/4));
s5 = repmat(s2_hinf, [1, 5]);
t = linspace(0, length(s5), samples*5); % 5 cycles
plot(t, s5);
grid on;
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