For and Break Stuck
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Hi everybody. I wrote a code but something is going wrong, I need at that point.
I need to stop the code at the gain of 0.5 and I need to take the values that I need as P and D. But The code does not do what I need. It always work around i = 65 and j = 65. What is the error ?
clear all; clc;
Kp = -10:0.31:10;
Kd = -10:0.31:10;
% n = [Kd Kp];
% d = [(1+Kd) (Kp+1)];
%
% [r,p,k] = residue(n,d);
A = zeros(length(Kp), length(Kd));
for i = 1:length(Kp)
for j = 1:length(Kd)
n = [Kd(j) Kp(i)];
d = [(1+Kd(j)) (Kp(i)+1)];
[r,p,k] = residue(n,d);
S = sum(r);
TF = tf(n,d);
[z, gain] = zero(TF);
if gain == 0.5
break;
end
% if S<0.6 && S>0.4
% A(i,j) = 1;
% else
% A(i,j) = 0;
% end
end
end
Antworten (1)
James Tursa
am 20 Mär. 2018
It is often better to use tolerances for floating point comparisons, unless you wrote the underlying code and you know that the result must be exactly 0.5. So this test
if gain == 0.5
should probably look something like this instead
if abs(gain - 0.5) < tol % for some appropriate value of tol
5 Kommentare
What do you mean ? What should I change ?
Berkcan Oz
am 21 Mär. 2018
Stephen23
am 21 Mär. 2018
You could start with tol=1e-5;
Berkcan Oz
am 21 Mär. 2018
Bearbeitet: Walter Roberson
am 21 Mär. 2018
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