Antworten (2)

John D'Errico
John D'Errico am 18 Mär. 2018
Bearbeitet: John D'Errico am 18 Mär. 2018

2 Stimmen

To answer the question you insist on asking multiple times.
L is a logical vector. C a character array.
L = rand(10,1) < .5
L =
10×1 logical array
1
1
0
1
1
0
1
1
1
1
C = reshape(char(L + '0'),5,2)
C =
5×2 char array
'10'
'11'
'01'
'11'
'11'

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am 18 Mär. 2018

Bearbeitet:

am 18 Mär. 2018

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