Entire Column Disappears After Sorting

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Mark Tenorio
Mark Tenorio am 10 Mär. 2018
Beantwortet: Mark Tenorio am 10 Mär. 2018
I'm trying to sort a column based on some indexing. I tried to copy the way it was done here https://stackoverflow.com/questions/16072984/sorting-cell-array-based-on-column-double-not-char-values but for a larger cell array.
I attached my code. My code will work for textfile1 but not textfile2 because of dimension mismatch. See attached for both text files. Pretend that the input (textfile1 and textfile2) are of class cell.
This is line 32:
number_Holder2 = number_Holder2(index_Ratings);
where the size of number_Holder2 is 5x1 after being run. However, before this line of code is run, the cell is 5x2 ... which I want it to be because when line 39 is run:
sorted_DoubleArray = [list(1,2:end);number_Holder2Complete]; %concatnate
I get a dimension error in my code.
Is there a way that I can adjust line 32 so that it wont remove a column?
Edit: Not allowed to use sortrows() unfortunately.
  4 Kommentare
Stephen23
Stephen23 am 10 Mär. 2018
Bearbeitet: Stephen23 am 10 Mär. 2018
@Mark Tenorio: the link I gave you is not for sortrows. I should know, I wrote it!
Mark Tenorio
Mark Tenorio am 10 Mär. 2018
Not sure if your link does it but I found a way. Just use a for loop to iterate through each column and index like that instead of trying to do it in one line of code.

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Mark Tenorio
Mark Tenorio am 10 Mär. 2018
Not sure if your link does it but I found a way. Just use a for loop to iterate through each column and index like that instead of trying to do it in one line of code.

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