Color Tracking in MATLAB - RGB
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Madeline Corrigan
am 16 Mai 2012
Kommentiert: Image Analyst
am 12 Jul. 2017
Hi,
I wrote code to track colors in MATLAB. The code plots three circles (Red, Blue, and Green) that follow the motion of colors moving on in front of the web cam (R, B, G). Red and blue work perfectly, but green does not. Any ideas? Here is my code after I set up the video acquisition:
% Get snapshot of current frame
snap = getsnapshot(vid);
% Extract red by subtracting red from grayscale
snap_red = imsubtract(snap(:,:,1), rgb2gray(snap));
snap_blue = imsubtract(snap(:,:,3), rgb2gray(snap));
snap_green = imsubtract(snap(:,:,2), rgb2gray(snap));
% Filter out noise
snap_red = medfilt2(snap_red, [3 3]);
snap_blue = medfilt2(snap_blue, [3 3]);
snap_green = medfilt2(snap_green, [3 3]);
% Convert new snapshot to binary
snap_red = im2bw(snap_red,0.18);
snap_blue = im2bw(snap_blue,0.18);
snap_green = im2bw(snap_green,0.18);
% Remove pixles less than 300px
snap_red = bwlabel(snap_red, 8);
snap_blue = bwlabel(snap_blue, 8);
snap_green = bwlabel(snap_green, 8);
% Label all connected components
bw_red = bwlabel(snap_red,8);
bw_blue = bwlabel(snap_blue,8);
bw_green = bwlabel(snap_green,8);
% Properties for each labeled region
stats_red = regionprops(bw_red, 'BoundingBox','Centroid');
stats_blue = regionprops(bw_blue, 'BoundingBox','Centroid');
stats_green = regionprops(bw_green, 'BoundingBox','Centroid');
% Display new image
drawnow
% Puts red objects in rectangular box
for object_red = 1:length(stats_red)
bb_red = stats_red(object_red).BoundingBox;
bc_red = stats_red(object_red).Centroid;
plot(bc_red(1),-bc_red(2),'or')
axis([0 300 -300 0])
end
hold on
% Puts blue objects in rectangular box
for object_blue = 1:length(stats_blue)
bb_blue = stats_blue(object_blue).BoundingBox;
bc_blue = stats_blue(object_blue).Centroid;
plot(bc_blue(1),-bc_blue(2),'ob')
axis([0 300 -300 0])
end
% Puts blue objects in rectangular box
for object_green = 1:length(stats_green)
bb_green = stats_green(object_green).BoundingBox;
bc_green = stats_green(object_green).Centroid;
plot(bc_green(1),-bc_green(2),'og')
axis([0 300 -300 0])
end
hold off
2 Kommentare
Vikash Varma
am 12 Jul. 2017
can anyone explain why we have to remove all those pixels less than 300 from a binary image which contains only either 0 or 1 ?
Image Analyst
am 12 Jul. 2017
Do you actually mean "remove all those blobs less than 300 pixels"? If so, do this
binaryImage = bwareaopen(binaryImage, 300);
Akzeptierte Antwort
Image Analyst
am 16 Mai 2012
Subtracting from the grayscale version of the image is a bad way to find the green, or any color for that matter. You need to look at the difference between the color you want and the average of the other two. For example this might give a better green signal:
greenDifference = abs(greenChannel - (redChannel + blueChannel)/2);
Then threshold on that. Cast them all to double first so you don't get any clipping.
6 Kommentare
Image Analyst
am 8 Nov. 2015
See my demo http://www.mathworks.com/matlabcentral/fileexchange/28512-simple-color-detection-by-hue It would be something like this
hsvImage = rgb2hsv(double(rgbImage));
h = hsvImage(:,:,1);
s = hsvImage(:,:,2);
v = hsvImage(:,:,3);
whitePixels = s < 0.2 & v > 0.8;
or something like that.
whitePixels is a binary image, or "mask". Feel free to modify the parameters.
Weitere Antworten (2)
Andrea
am 15 Feb. 2013
Hello, to detect green should change a parameter in this condition:
%%snap_green = im2bw(snap_green,0.18);%%
0.18 is to detect objects with a light green colored and sometimes do not want to detect. I advise you to try with a strong green and put it to 0.09 parameter. I hope you still serve. Andrea
0 Kommentare
daher
am 27 Dez. 2013
Hi, i have a question.. assuming that we have to track the first identified blue object that appears in a video (O1) Next, another object (O2) with the same color (using HSV presentation) appears
how to distinguish between them and to keep tracking O1 no matter what will be identified later in the video without referring to geometry features of each object.. Any suggestions?
0 Kommentare
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