Reshape matrix to have the same value every 30 cells

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Nikolas Spiliopoulos
Nikolas Spiliopoulos am 19 Feb. 2018
Kommentiert: Jos (10584) am 19 Feb. 2018
Hi All,
I have a question: I have a matrix
A=[10; 20; 30; 40; 50; 50; 60]
How can I reshape it in order to have a matrix (7x30) X 1 such that the first 30 values are A(1), the next 30 have value of A(2), and so on...
thanks
nikolas

Akzeptierte Antwort

Guillaume
Guillaume am 19 Feb. 2018
This is not a reshape it's a repmat:
repmat(A, 1, 30)
  1 Kommentar
Jos (10584)
Jos (10584) am 19 Feb. 2018
Just to be nitpicking :D ... the first 30 values of A, retrieved by A(1:30) will be [10 20 30 40 50 60 70 10 20 ...] because A is a column vector and Matlab stores values columnwise.

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Weitere Antworten (1)

Birdman
Birdman am 19 Feb. 2018
Bearbeitet: Birdman am 19 Feb. 2018
B=mat2cell(repmat(A,1,30),ones(1,7),30)
type A{1} and the result will be 30 10's.
  2 Kommentare
Nikolas Spiliopoulos
Nikolas Spiliopoulos am 19 Feb. 2018
Thanks for the reply however I am getting an error "Inner matrix dimensions must agree"
Guillaume
Guillaume am 19 Feb. 2018
You're on a version earlier than R2016b. You have to use bsxfun on earlier versions.
Not that it matters, since the answer has completely changed.

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