Sort all columns in a cell array with labels
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Hello everyone
I have the following cell array with text and numeric data:
>> M
M =
5×4 cell array
'' 'Ana' 'Delta' 'Oscar'
'B' [0.9058] [0.9058] [0.9058]
'C' [0.1270] [0.1270] [0.1270]
'D' [0.9134] [ 4] [ 2]
'E' [0.6324] [0.6324] [0.6324]
I would like to sort the data in columns 2, 3 and 4 in descending order (largest to smallest) but also with labels (column 1) and also with labels Ana, Delta and Oscar. I am aware that sortrows can be used for sorting data using a particular column, but I am not sure of the indexing for sortrows or an efficient way of sorting data in columns 2-4 in my cell array M and at the same time having labels next to them.
Thank you for your help.
Suha.
2 Kommentare
Stephen23
am 13 Feb. 2018
Bearbeitet: Stephen23
am 13 Feb. 2018
@Suha: you should really consider putting your data into a table, which natively store data with headers. Then you could apply lots of other functions to the data without having to worry about the first row and column being special cases, e.g. sorting the rows without requiring any indexing at all. It also stores the columns as arrays of an appropriate class, which makes working with the data much easier (putting lots of scalar numeric data into cells of a cell array just makes working with numeric data much more complex than it needs to be).
Akzeptierte Antwort
Stephen23
am 13 Feb. 2018
Bearbeitet: Stephen23
am 13 Feb. 2018
If you do not want to use a table then you would be better off keeping your numeric and cell-of-character data separately, e.g.:
hdr = {'Ana','Delta','Oscar'}
typ = {'B','C','D','E'};
mat = [0.9058,0.9058,0.9058;...
0.1270,0.1270,0.1270;...
0.9134, 4, 2;...
0.6324,0.6324,0.6324];
Then you can trivially sort by rows as you choose:
>> [mat,idx] = sortrows(mat)
mat =
0.12700 0.12700 0.12700
0.63240 0.63240 0.63240
0.90580 0.90580 0.90580
0.91340 4.00000 2.00000
idx =
1
2
3
4
>> typ = typ(idx);
>> typ{:}
ans = B
ans = C
ans = D
ans = E
5 Kommentare
Stephen23
am 13 Feb. 2018
@Suha: each column might have a different order: is that what you want?
>> [mat,idx] = sort(mat,1)
mat =
0.12700 0.12700 0.12700
0.63240 0.63240 0.63240
0.90580 0.90580 0.90580
0.91340 4.00000 2.00000
idx =
2 2 2
4 4 4
1 1 1
3 3 3
>> out = typ(idx)
'C' 'C' 'C'
'E' 'E' 'E'
'B' 'B' 'B'
'D' 'D' 'D'
Weitere Antworten (1)
Birdman
am 13 Feb. 2018
Bearbeitet: Birdman
am 13 Feb. 2018
Something like this?
[~,idx]=sort(cell2mat(M(2:end,2:end)),1,'descend');
M(sort(idx)+1,:)=M(idx+1,:)
or
[~,idx]=sortrows(M(2:end,2:end),'descend');
M(sort(idx)+1,:)=M(idx+1,:)
7 Kommentare
Birdman
am 13 Feb. 2018
It worked perfectly in my case, where each column was sorted independently. Make sure you enter the code correctly, otherwise it should work. I can not attach a screenshot of it at the moment.
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