for loop with linspace

101 Ansichten (letzte 30 Tage)
Rob
Rob am 9 Feb. 2018
Kommentiert: Sebastian Castro am 10 Feb. 2018
Hi all, I'm trying to get the following for loop statement to work. I'm doing shear force calculations for different portions of a beam. I get this as error 'Subscript indices must either be real positive integers or logicals'.
b =input('Enter the length of the beam ');
u =input('Enter the load (N/m) ');
R_side = u*b/3;
R_center = R_side;
d = 0.17 * b;
l = 0.33 *b;
x = linspace(0,b,100);
for i =length(x)
if i<= d
sh(i) = -u*x;
elseif x<= d+l
sh(i) = -u*x + R_side;
elseif x<= d+2*l
sh(i) = -u*x + R_side + R_center;
else
sh(i) = -u*x + R_center + 2*R_side;
end
end
plot(x,sh(i))
xlabel(' Length of beam, [m]','FontSize',20);
ylabel(' Shear force, [N]','FontSize',20);
title('Shear Force Diagram','FontSize',20);
  2 Kommentare
Image Analyst
Image Analyst am 9 Feb. 2018
Not what I get:
Enter the length of the beam 4
Enter the load (N/m) 5
Subscripted assignment dimension mismatch.
Error in test4 (line 21)
sh(i) = -u*x + R_center + 2*R_side;
What values did you enter?
Walter Roberson
Walter Roberson am 9 Feb. 2018
Notice that
for i =length(x)
executes exactly once, with i = 100 (that is, the length of x)

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Sebastian Castro
Sebastian Castro am 9 Feb. 2018
I see 2 things here
First, the for-loop should start from the first index and stop at the length of x. Right now, your code is saying that i is only one value ( length(x) ).
for i=1:length(x)
Secondly, just as you're assigning each individual element of the sh vector as sh(i), you want to do the same with x instead of trying to perform operations on the entire array. So, for example:
sh(i) = -u*x(i)
- Sebastian
  2 Kommentare
Rob
Rob am 10 Feb. 2018
Okay so now that I followed your corrections I'm getting a blank plot/vectors must be the same length error. Is it because I should make a vector with the output of sh? How could I store every value of sh(i)
as in save_case = 0;
save_case = save_case + 1;
sh_output(save_case) = sh?
Sebastian Castro
Sebastian Castro am 10 Feb. 2018
I think you need to remove the indexing from the plot, since you want the whole sh vector. The following command should do it:
plot(x,sh)
- Sebastian

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by