How to append several elements to a single element in an array?

I have an array like:
A = [1 2 3 4 5 6 7 8 9 10];
I want to merge all the elements into a single element, like:
A = [12345678910];
but I cannot see any clear way to do so, as functions like 'reshape' or 'horizcat' simple place all the elements vertically, instead of appending all the values into one long element.
Any help would be really appreciated!
Thanks.

1 Kommentar

Note to others: see my answer if you want a simpler, faster solution.

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 Akzeptierte Antwort

Birdman
Birdman am 31 Jan. 2018
Bearbeitet: Birdman am 31 Jan. 2018
%%to see the complete number with all digits
format longg
str2double(strjoin(string(A),''))

6 Kommentare

I added it to the code:
A = [1 2 3 4 5 6 7 8 9 10];
%to see the complete number with all digits
format long
B = str2double(strjoin(string(A),''));
I am afraid it produces '1.234567891000000e+10' as the value within B, am I implementing it incorrectly?
Birdman
Birdman am 31 Jan. 2018
Bearbeitet: Birdman am 31 Jan. 2018
Type
format longg
with 2 g. This only changes its display format.
I am still getting the same result, is there anything else I need to include in my implementation of it?
Birdman
Birdman am 31 Jan. 2018
Bearbeitet: Birdman am 31 Jan. 2018
No you don't. But be aware of the fact that
12345678910
is displayed in a scientific form of
1.2346e+10
by default. My only aim was to show you that the number is equal to what you want. So the following code:
B = str2double(strjoin(string(A),''));
actually does what you want.
You are welcome!

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Weitere Antworten (1)

Stephen23
Stephen23 am 31 Jan. 2018
Bearbeitet: Stephen23 am 31 Jan. 2018
Much faster and simpler than using string, strjoin, and str2double:
>> A = [1 2 3 4 5 6 7 8 9 10];
>> N = sscanf(sprintf('%d',A),'%f')
N = 12345678910

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