subtract values inside a array
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any help will be great. Thank you

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Birdman
am 22 Jan. 2018
Not the most efficient, but a solution:
init=50;
a=[init 12 2 6 8 6 2 12]
for i=1:numel(a)-1
val=a(1)-a(2);
b(i)=val;
a(1)=[];
a(1)=val;
end
disp(b)
1 Kommentar
Mohamed Musni
am 22 Jan. 2018
Mohammed Bahubayl
am 22 Jan. 2018
Bearbeitet: Mohammed Bahubayl
am 22 Jan. 2018
function output =difff(x)
intial=50;
output=[];
for i=1:length(x)
output(end+1)=intial-x(i);
intial=output(end);
end
end
1 Kommentar
Mohamed Musni
am 22 Jan. 2018
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