Akzeptierte Antwort

Stephen23
Stephen23 am 22 Jan. 2018
Bearbeitet: Stephen23 am 22 Jan. 2018

1 Stimme

MATLAB code should be beautiful, simple, and efficient:
>> V = [12;2;6;8;6;2;12];
>> 50+cumsum(-V)
ans =
38
36
30
22
16
14
2

Weitere Antworten (2)

Birdman
Birdman am 22 Jan. 2018

1 Stimme

Not the most efficient, but a solution:
init=50;
a=[init 12 2 6 8 6 2 12]
for i=1:numel(a)-1
val=a(1)-a(2);
b(i)=val;
a(1)=[];
a(1)=val;
end
disp(b)

1 Kommentar

Mohamed Musni
Mohamed Musni am 22 Jan. 2018
Thank you very much. this will help me a lot. have a nice day!

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Mohammed Bahubayl
Mohammed Bahubayl am 22 Jan. 2018
Bearbeitet: Mohammed Bahubayl am 22 Jan. 2018

1 Stimme

function output =difff(x)
intial=50;
output=[];
for i=1:length(x)
output(end+1)=intial-x(i);
intial=output(end);
end
end

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