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My code is as follows:
alpha = 0.5;
beta = 0.1;
a_0 = 1;
dr = 0.1;
dt = input('Value of dt:');
h = 0.001;
c_inf = 0;
c_a = 1;
c_s = 2;
mesh_points = 3;
rho = dt/(dr)^2;
R= 30;
N_i = R/dr;
t_diss = 5.8;
N_t = t_diss/dt;
if rho >= 0.5;
disp('Invalid dt value');
return;
end
for i=1:N_i;
r(i)=(i-1)*dr;
if r(i)< a_0
c(i,1)= c_s;
else
c(i,1)= c_inf;
end
end
a(1) = a_0;
for j = 1:N_t -1;
b_1 = floor (a(j)/dr) + 2;
b_2 = b_1 + 1;
c_ah = (a(j)+h-b_1)*(a(j)+h-b_2)*(c_a)/((a(j)-b_1)*(a(j)-b_2))+h*(a(j)+h-b_2)*c(b_1,j)/((b_1-a(j))*(b_1-b_2)) + h*(a(j)+h-b_1)*c(b_2,j)/((b_2-a(j))*(b_2-b_1));
dc_dr = ((c_ah)-c_a)/h;
a(j+1) = a(j) +dt*beta*dc_dr;
for i=2:N_i - 1;
if r(i) > a(j+1);
d = rho - (rho/(i-1)) - (a(j)^2)*(alpha-1)*(a(j+1)-a(j))/(2*(i-1)^2*(dr)^3);
e = 1-2*rho;
f = rho + (rho/(i-1)) + (a(j)^2)*(alpha-1)*(a(j+1)-a(j))/(2*(i-1)^2*(dr)^3);
c(i, j+1) = d*c(i-1,j) + e*c(i,j) + f*c(i+1, j);
elseif r(i) == a(j+1);
c(i,j+1) = c_a;
else c(i,j+1) = c_s;
end
disp(c(i,j));
end
c(1, j+1) = c(2, j+1);
end
It basically calculates concentration near a dissolving sphere but when it gets to disp(c(i,j)) I get caught in loop of displaying numbers that change periodically. Any ideas?
Akzeptierte Antwort
Weitere Antworten (1)
Richard Brown
am 7 Mai 2012
1 Stimme
Your code works fine. If you remove the disp statement (which is causing it to slow down heaps), you'll find that it runs completely in around 10 seconds or so.
2 Kommentare
Richard Brown
am 7 Mai 2012
Oh, and a hint: Select all the code, then Text->Smart Indent
Image Analyst
am 7 Mai 2012
Cool. Nice trick that I didn't know about.
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