Regarding Iteration
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Hi all,
for j=1:30
x(:,j) = unifrnd(minsvc(j), maxsvc(j), no_pop,1);
if busdata(j,2)==0
rchoices = size(x(:,j));
randchoice = x(rchoices(1),j);
Qg(j,17)=randchoice;
else
Qg(j,17)=busdata(j,17);
end
v(:,j)=unifrnd(minv(j), maxv(j),no_pop,1);
end
Here, in this if the busdata(j,2)==0 condition is satisfied, i need to execute that if for only once that too for random 'j' values. Is there any solution for this?
1 Kommentar
Jan
am 4 Mai 2012
I do not understand the question.
Antworten (1)
Image Analyst
am 4 Mai 2012
Try adding a break statement:
for j=1:30
x(:,j) = unifrnd(minsvc(j), maxsvc(j), no_pop,1);
if busdata(j,2)==0
rchoices = size(x(:,j));
randchoice = x(rchoices(1),j);
Qg(j,17)=randchoice;
break; % Exit the for loop.
else
Qg(j,17)=busdata(j,17);
end
v(:,j)=unifrnd(minv(j), maxv(j),no_pop,1);
end
However, if j = 42 when the condition becomes true and it breaks, then the for loop has already executed 42 times before it exits, so in that regard, like Jan, I'm a bit confused.
2 Kommentare
Muruganandham Subramanian
am 4 Mai 2012
Jan
am 4 Mai 2012
I still do not understand the problem.
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