How to call the rows of a matrix without the for loop
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Waheeb Butt
am 12 Dez. 2017
Kommentiert: Waheeb Butt
am 12 Dez. 2017
Hi I have a matrix A=[1 2 3 4 5;6 7 8 9 10; 11 12 13 14 15] and I want to call each row of the matrix one by one as an input to my program. i.e, A(1,:) is taken as first input, A(2,:) is the second input and finally A(3,:), just like it is done in a loop, but is there any way that I can do the same without using a for loop.
Any help would be much appreciated.
1 Kommentar
Fangjun Jiang
am 12 Dez. 2017
Do you want MyFun(A(1,:),A(2,:),A(3,:)), or MyFun(A(1,:)), MyFun(A(2,:)), MyFun(A(3,:))? How do you plan to do it using for-loop?
Akzeptierte Antwort
KL
am 12 Dez. 2017
Probably convert them to cell array and then the use of comma-separated lists,
B = num2cell(A,2)
and then
your_program(B{:})
3 Kommentare
KL
am 12 Dez. 2017
Bearbeitet: KL
am 12 Dez. 2017
...for further processing in your_program...
if you're talking about handling them inside your_program, it's pretty normal like,
function out = your_program(a,b,c)
x = a(1);
...
or if you are talking about indexing only specific elements while calling your_program, you should create your cell array with those elements.
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!