- a non-scalar structure with scalar fields (or char vectors), or
- a scalar structure with non-scalar fields?
Put in alphabet order a structure only by one field
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Hi, i have a struct called "users" that contains fields such as "name","username","password".I want do display all the structure's data but it has to be alphabettically organized by name. How can i do this using sort?
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Walter Roberson
am 18 Dez. 2017
[~, sortidx] = sort({users.name});
users = users(sortidx);
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Walter Roberson
am 18 Dez. 2017
True. If it is a scalar structure with cell arrays of character vectors, and will all fields having the same number of entries (but fields possibly being different data types from each other)
[~, sortidx] = sort(users.name);
users = structfun(@(F) F(sortidx), users, 'uniform', 0);
Harish Ramachandran
am 18 Dez. 2017
Bearbeitet: Harish Ramachandran
am 18 Dez. 2017
Hello,
Unfortunately, there is no direct way to sort a structure according to one of the field. The steps below involve transforming the structure into a table, perform the ' sortrows' operation and reverting back to a structure. I have also attached a couple of relevant links which you can check out.
- Create a predefined structure - users
users = struct('name', {'Noah', 'Liam', 'Mason', 'Jacob', 'William', 'Ethan', 'James', 'Alexander'},...
'username', {'NH', 'LM', 'MN', 'JB', 'WM', 'EN', 'JS', 'AR'},...
'password', {'NH147', 'LM258', 'MN@234', 'JB369', 'WM1991', 'EN4567', 'JS#345', 'AR/*-789'})
- Convert the structure into a table.
user_Table = struct2table(users);
- You can view the contents of the table using the ' disp' function:
disp(user_Table)
- Sort the table with the key being the 'name' column.
user_Table = sortrows(user_Table,'name');
- Revert back to a structure
users = table2struct(user_Table);
You can also check out the links below:
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