Allocating values in 1d matrix
    3 Ansichten (letzte 30 Tage)
  
       Ältere Kommentare anzeigen
    
    Da'Moon
 am 6 Dez. 2017
  
    
    
    
    
    Bearbeitet: Da'Moon
 am 6 Dez. 2017
            B = p * ones(327,245,2, uint8); can i do it with a loop?
0 Kommentare
Akzeptierte Antwort
  Image Analyst
      
      
 am 6 Dez. 2017
        No need for for loops, especially ones that don't work. Simply use ones:
B = p * ones(327,245,2, 'uint8');
1 Kommentar
  Image Analyst
      
      
 am 6 Dez. 2017
				Try this:
p=uint8(0);
for L = 3 : -1 : 1 
    for row = 327 : -1 : 1
        for col = 245 : -1 : 1
            B(row, col, L)=p;            
        end
    end
end
It's a very inefficient way of doing it. I reverse the indexes to try to make it more efficient though. You should NOT want to do it this way.
Weitere Antworten (0)
Siehe auch
Kategorien
				Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!

