Datenum Problem in Octave???
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FishermanJack
am 13 Nov. 2017
Kommentiert: FishermanJack
am 13 Nov. 2017
I have an Problem with implementing a Matlab Code into Octave. i have an dt = char of the size 5x21
.
dt =
yearmonthdayt [hh:mm]
2016Jan 01 00:00
2016Jan 01 00:15
2016Jan 01 00:30
2016Jan 01 00:45
>> and use
datenum( dt, 'yyyymmmddHH:MM' );
but i get the following error message in Octave:
error: datevec: DATE not parsed correctly with given Format
error: called from datevec at line 147 column 11 datenum at line 104 column 40
5 Kommentare
dpb
am 13 Nov. 2017
Octave isn't Matlab despite it being similar and mostly syntax-similar.
While is OT here, from the error message I'd guess the problem is the format string isn't correct case for the month/hour/day fields...there's a difference between the old datenum and the new(er) datetime in who's upper- and who's lower- case; check the doc for "who's who in the zoo"...
Walter Roberson
am 13 Nov. 2017
The first entry is not parseable. The second others might have problems because of the spaces.
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