Write a function called year2016 that returns a row-vector of struct-s whose elements correspond to the days of a month in 2016 as specified by the input argument. If the input is not an integer between 1 and 12, the function returns the empty array. Each struct should contain three fields with these (exact) field names: “month”, “date”, and “day” (all lower case).
  • The month field must contain a string with the name of the month (first letter capitalized).
  • The date field must contain a scalar specifying the day of the month.
  • The day field must contain the three-letter abbreviation of the day chosen from this list: 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'.
For example, here is a call of the function followed by a command that shows the seventh element of the struct array that is returned by the function:
>> m = year2016(2);
>> m(7)
ans =
month: 'February'
date: 7
day: 'Sun'
My code is here;
function x = year2016(m)
year2016.month = {'January';'February';'March';'April';'May';'June';'July';'August';'September';'October';'November';'December'};
TypeList = {'Mon','Tue','Wed','Thu','Fri','Sat','Sun'};
for k = 1:numel(TypeList)
x = TypeList{k};
if month >0 && month<=12
return;
end
end
x = 'NONE';
I know that it has many error but I haven't associate month , day and date. Please help me?

3 Kommentare

Rik
Rik am 7 Nov. 2017
One of the many problems with this function is that your input is m, but the rest of the function uses month. You should think about the flow of your program: with an example input of 2, what are the steps your function should take before it gets to the end or a return (be aware that a return just returns control, it doesn't check if outputs are already created).
Another thing that really jumps out, is that you use a variable with the same name as the function. I believe this will return an error in future releases, but currently it is just bad programming practise.
Walter Roberson
Walter Roberson am 27 Apr. 2018
Please do not close questions that have an answer.

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Antworten (2)

shah109
shah109 am 24 Dez. 2017
Bearbeitet: Walter Roberson am 25 Dez. 2017

1 Stimme

% I modified this function from stephen cobeldick post
function out = year2016(m)
if ~isscalar(m) || m <1 || m~=fix(m)
out = [];
else
VN = datenum([2016,m,1]):datenum([2016,m+1,1])-1;
DN = 1+mod(VN-3,7);
MC = {'January';'February';'March';'April';'May';'June';'July';'August';'September';'October';'November';'December'};
DC = {'Mon','Tue','Wed','Thu','Fri','Sat','Sun'};
out = struct('day',DC(DN),'date',num2cell(1:numel(VN)));
[out(:).month] = deal(MC{m});
end

2 Kommentare

Emma Sellers
Emma Sellers am 4 Jan. 2019
I have tried using a code similar to this and I get an error when the code runs
m = [1 2 ]
what needs to be added?
I tried adding sizeof(m)>1 to line three and that did not help.
Walter Roberson
Walter Roberson am 4 Jan. 2019
that should be caught by the isscalar test.

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Ugur Ulas
Ugur Ulas am 10 Jan. 2018
Bearbeitet: Ugur Ulas am 10 Jan. 2018

0 Stimmen

Hello, it s another solution:
function m = year2016(A,B)
day_no = datenum(2016,A,1)-datenum(2016,0,1);
day_mod = mod((B+day_no+4),7);
if day_mod == 0
day_mod = 7
end
month = {'January' 'February' 'March' 'April' 'May' 'June' 'July' 'August' 'September' 'October' 'December' 'November'};
day = {'Mon' 'Tue' 'Wed' 'Thu' 'Fri' 'Sat' 'Sun'};
if 0>A || 12<A || 0>B || (datenum(2016,A+1,1)-datenum(2016,A,1))<B
m = struct([])
else
a = month{A};
b = day{day_mod};
m = struct('month',a,'date', B ,'day',b);
end
end

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Gefragt:

am 7 Nov. 2017

Kommentiert:

am 4 Jan. 2019

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