why do i get NaN?

b, z numbers come out but from there onwards e, w, j, k, t and the others leave NaN why?

b=(str2double(get(handles.edit12,'string'))-str2double(get(handles.edit10,'string')))/(str2double(get(handles.edit11,'string'))-str2double(get(handles.edit8,'string')))
z=(str2double(get(handles.edit14,'string'))-str2double(get(handles.edit12,'string')))/(str2double(get(handles.edit13,'string'))-str2double(get(handles.edit11,'string')))
e=(str2double(get(handles.edit16,'string'))-str2double(get(handles.edit14,'string')))/(str2double(get(handles.edit15,'string'))-str2double(get(handles.edit13,'string')))
w=(str2double(get(handles.edit18,'string'))-str2double(get(handles.edit16,'string')))/(str2double(get(handles.edit17,'string'))-str2double(get(handles.edit15,'string')))
j=(str2double(get(handles.edit20,'string'))-str2double(get(handles.edit18,'string')))/(str2double(get(handles.edit19,'string'))-str2double(get(handles.edit17,'string')))
k=(z-b)/(str2double(get(handles.edit13,'string'))-str2double(get(handles.edit18,'string'))) 
t=(e-z)/(str2double(get(handles.edit15,'string'))-str2double(get(handles.edit11,'string')))
l=(w-e)/(str2double(get(handles.edit17,'string'))-str2double(get(handles.edit13,'string')))
n=(j-w)/(str2double(get(handles.edit19,'string'))-str2double(get(handles.edit15,'string')))
b0=str2double(get(handles.edit10,'string'))
y=b0+b*(x-str2double(get(handles.edit8,'string')))+k*(x-str2double(get(handles.edit8,'string')))*(x-str2double(get(handles.edit11,'string')))

[Erwin Avendaño]

The method is interpolation of newton

[Image Analyst]

Post a screenshot of your GUI so we can see what numbers you've typed into the edit fields.

[Erwin Avendaño]

wait a moment please a curious fact is that I did the operations with my calculator and I do not leave a division of 0/0 I get a number

[Erwin Avendaño]

Answer 1

[Walter Roberson]

I recommend doing each str2double only once and assign each to a meaningful variable name and then do the calculations. You can examine the variables to see if you got any nan, which is possible if the corresponding string did not represent a scalar double. You can also get nan from 0/0

[Erwin Avendaño]

What do you mean by a significant variable name? I did the calculations with a manual calculator and it does not give me a 0/0 gives me a number is what I do not understand is curious because the first two if they give me a number as I mentioned before but from then on e, w, j give me NaN

[Erwin Avendaño]

[Walter Roberson]

What you posted does not tell us what is stored in the strings. Show us the result of get() of each of the handles used in the formula

[Erwin Avendaño]

It is solving a problem with my program that I check several times that it was fine so I tried another problem and this one if I solved it well and if no mistake no longer told me NaN thank you