Error: In an assignment A(I) = B, the number of elements in B and I must be the same.
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
LALE ASIK
am 15 Okt. 2017
Kommentiert: LALE ASIK
am 16 Okt. 2017
Hello everyone. Here is the code that gives me the following error:
In an assignment A(I) = B, the number of elements in B and I must be the same.
Error in SeasonalityLVEbif>Preypred (line 33)
Ydot(1) =(alpha1*(Ke-Y(1)))+Ke*pi*Y(2)/6;
The code :
function SeasonalityLVEbif
rect=[200 80 700 650];%fix the window size and position
set(0,'defaultfigureposition',rect);
global alpha1 b P theta q c a e d
alpha1=0.5; b=1.2; P=0.025; theta= 0.03;q=0.0038; c= 0.81; a= 0.25; e=0.8; d=0.25;
option=odeset('AbsTol',1e-11,'RelTol',1e-11);
inc=[0.01:1:220]';
time=[ inc ] ;
limit=[200:1:220];
ymin=[];
ymax=[];
for Ke=0.01:0.05:2,
IC=[1.5 1 0 0.5 0.25 ];
[t,U]=ode45(@Preypred,time,IC);
u1=U(limit,1);
ymin=[ymin,min(u1)];
ymax=[ymax,max(u1)];
end
X=0.01:0.05:2;
figure
plot(X, ymin,'g.',X, ymax,'k.');
legend('grazer min','grazer max'),
hold on
xlim([0.01 2]);
title('Bifurcation diagram for LVE model','FontSize',12)
xlabel('Ke, the equilibrium carrying capacity');
ylabel('grazer','Rotation',90);
function [Ydot] = Preypred(t,Y)
global alpha1 Ke b P theta q c a e d
Ydot(1) =(alpha1*(Ke-Y(1)))+Ke*pi*Y(2)/6;
Ydot(2) =Y(2)*(1-Y(2)^2-Y(3)^2)-2*pi*Y(3)/6;
Ydot(3) = Y(3)*(1-Y(2)^2-Y(3)^2)+2*pi*Y(2)/6;
Ydot(4) = b*Y(4)*(1-Y(4)/(min(Y(1),(P-theta*Y(5))/q)))-c*Y(4)*Y(5)/(a+Y(4));
Ydot(5) = e*min(1,((P-theta*Y(5))/Y(4))/theta)*c*Y(4)*Y(5)/(a+Y(4))-d*Y(5);
Ydot=Ydot';
Could you please help me to fix it?
1 Kommentar
Akzeptierte Antwort
KSSV
am 16 Okt. 2017
function SeasonalityLVEbif
rect=[200 80 700 650];%fix the window size and position
set(0,'defaultfigureposition',rect);
% global alpha1 b P theta q c a e d
values = struct ;
values.alpha1=0.5;
values.b=1.2;
values.P=0.025;
values.theta= 0.03;
values.q=0.0038;
values.c= 0.81;
values.a= 0.25;
values.e=0.8;
values.d=0.25;
option=odeset('AbsTol',1e-11,'RelTol',1e-11);
inc=[0.01:1:220]';
time=[ inc ] ;
limit=[200:1:220];
ymin=[];
ymax=[];
for Ke=0.01:0.05:2
IC=[1.5 1 0 0.5 0.25 ];
[t,U]=ode45(@Preypred,time,IC,[],values,Ke);
u1=U(limit,1);
ymin=[ymin,min(u1)];
ymax=[ymax,max(u1)];
end
X=0.01:0.05:2;
figure
plot(X, ymin,'g.',X, ymax,'k.');
legend('grazer min','grazer max'),
hold on
xlim([0.01 2]);
title('Bifurcation diagram for LVE model','FontSize',12)
xlabel('Ke, the equilibrium carrying capacity');
ylabel('grazer','Rotation',90);
function [Ydot] = Preypred(t,Y,values,Ke)
Ydot = zeros(1,5) ;
alpha1 = values.alpha1 ;
b = values.b ;
P = values.P ;
theta = values.theta ;
q = values.q ;
c = values.c ;
a = values.a ;
e = values.e ;
d = values.d ;
Ydot(1) =(alpha1*(Ke-Y(1)))+Ke*pi*Y(2)/6;
Ydot(2) =Y(2)*(1-Y(2)^2-Y(3)^2)-2*pi*Y(3)/6;
Ydot(3) = Y(3)*(1-Y(2)^2-Y(3)^2)+2*pi*Y(2)/6;
Ydot(4) = b*Y(4)*(1-Y(4)/(min(Y(1),(P-theta*Y(5))/q)))-c*Y(4)*Y(5)/(a+Y(4));
Ydot(5) = e*min(1,((P-theta*Y(5))/Y(4))/theta)*c*Y(4)*Y(5)/(a+Y(4))-d*Y(5);
Ydot=Ydot';
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Argument Definitions finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!