Help, secant method by recursion

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Sun Woo Kim
Sun Woo Kim am 14 Okt. 2017
Beantwortet: Kinza Shahzad am 1 Jun. 2018
I'm trying to write a function that uses the secant method to find a root of the function.
I'm required to write both the iterative and recursive method.
So far, I finished writing the iterative but cannot finish the recursive.
The iterative is
function root = secanti(n, x0, x1, err)
while true
xi = (x0 * feval(n,x1) - x1 * feval(n, x0))/(feval(n,x1) - feval(n,x0));
if abs((xi-x1)/xi) < err
root = xi;
break
else
x0 = x1;
x1 = xi;
end
end
end
The one I have for recursive so far is
function xi = secantr(n, x0, x1, err)
xi = (x0 * feval(n,x1) - x1 * feval(n, x0))/(feval(n,x1) - feval(n,x0));
if abs((xi-x1)/xi) < err
return
end
x0 = x1;
x1 = xi;
secantr(n,x0,x1,err)
end
The recursive function keeps giving a different value from the iterative.
Is there any way to improve my recursive function? Thank you

Akzeptierte Antwort

Jan
Jan am 14 Okt. 2017
All you need is to catch the output:
xi = secantr(n,x0,x1,err);
^^^^

Weitere Antworten (1)

Kinza Shahzad
Kinza Shahzad am 1 Jun. 2018
how to run these codes ? :/m having some errors

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