Hi,
I have a cell matrix:
'56' 'mat find false' '89 mm' 'mat 96 kl'
I want to split:
  1. 'mat find false' --> 'mat' 'find false' (one cell to two cells)
  2. 'mat 96 kl' -->'mat' '96 kl'
desired Output:
'56' 'mat' 'find false' '89 mm' 'mat' '96 kl'
Many thanks in advance,

 Akzeptierte Antwort

Cedric
Cedric am 28 Sep. 2017
Bearbeitet: Cedric am 28 Sep. 2017

2 Stimmen

Or regexp-based: if
C = {'56', 'mat find false', '89 mm', 'mat 96 kl'} ;
then
result = regexp(C, '(mat)?\s?(.*)', 'tokens', 'once') ;
result = [result{:}] ;
result(cellfun(@isempty, result)) = [] ;
outputs:
result =
1×6 cell array
'56' 'mat' 'find false' '89 mm' 'mat' '96 kl'

2 Kommentare

Jan
Jan am 28 Sep. 2017
As usual I mention that cellfun('isempty') is faster than cellfun(@isempty), because it does not call a Matlab function in a loop, but checks the emptiness inside the Mex function.
Cedric
Cedric am 28 Sep. 2017
Bearbeitet: Cedric am 28 Sep. 2017
Thanks Jan!
I'll have to frame the following on my wall:

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Weitere Antworten (1)

Rik
Rik am 28 Sep. 2017
Bearbeitet: Rik am 28 Sep. 2017

1 Stimme

Easy to solve with looping through the list from the end:
for n=length(c):-1:1
idx=strfind(c{n},' ');
if ~isempty(idx)
c((n+1):(end+1))=c(n:end);
c{n}(idx(1):end)=[];
c{n+1}(1:idx(1))=[];
end
end

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