Vectorised cell search and logical indexing
Ältere Kommentare anzeigen
Hello, I would like to know if there is a vectorised/cellfun/better approach to the loop below:
% Find Key 4 in block_new{:}(1,1)
Key4 = '=x';
index4 = cellfun(@(x)regexp(x, Key4), block_new, 'UniformOutput', false);
Logic = false(length(index4),1);
for i = 1 : length(index4)
Logic(i) = ~isempty(cell2mat(index4{i}(1,1)));
end
index4 = Logic;
block_set = block_new(:,index4);
Where the cells in the 1 X m cell array, block_new are in themselves cell arrays of various sizes.
I have already tried the following:
find(~cellfun(@isempty,index4{:}(1,1)))
Thanks in advance.
3 Kommentare
Jos (10584)
am 21 Sep. 2017
what does block_new contain? Is it a cell array of strings?
Joshua
am 21 Sep. 2017
Jan
am 21 Sep. 2017
~isempty(cell2mat(index4{i}(1,1)));
If the output of cell2mat is empty, the cell must have been empty already. What about:
~isempty(index4{i}{1})
instead?
Please post a relevant input array.
Antworten (1)
Jos (10584)
am 21 Sep. 2017
regex can work on a cell array of strings directly:
block_new = {'abcd=x','abcd','a=xbc=x'}
index4 = regexp('block_new','=x')
3 Kommentare
Joshua
am 21 Sep. 2017
Jos (10584)
am 21 Sep. 2017
Some cells are cell array of strings themselves? Kind of complicated data structure ...
As mentioned by Jan, it would be simpler if you would attach a sample data set. Also, if you could describe in words what you are trying to achieve, that could help because you are doing a lot of operations that seem unnecessary (but that may in fact be necessary depending the final purpose).
Kategorien
Mehr zu Data Type Conversion finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!